User:SeptemberStoltenberg

percentage voltage rise "a" in a Hochspannungstrafo

Hello together!

I wonder how you the formula for the percentage voltage rise "a": a = (2 * pi * 50 Hz * L * I1) / U1 infers??? The inductance L of the transformers is calculated from a Kurzschlussverusch.

For "a", the result is used to calculate the translation factor "F" with capacitive loading of the Hochspannungsprüftransformators: F = ü (1 + a/100)

This is "ü": ü = U2/U1.

I would be very grateful for any help on the derivation of "a"! Moin...

Quote originally posted by Reno show post a = (2 * pi * 50 Hz * L * I1) / U1... Without knowing what should be "a"...

2 * Pi * 50 Hz * L is the HV construction of the inductor. This is multiplied by the current the voltage across them.

So is there a = U2 / U1 (If one neglects the real shares). Moin Moin harmonic,.

Thank you first of all for your reply. Like you I substation installation even thinking about, but it doesn't fit somehow. A capacitive load of transformers, I have indeed the capacity or even the self-capacitance of the transformer next to the transformer inductance. I've uploaded two images where I have done the calculation.

The challenge is to calculate the transmission ratio in relation to primary current and primary. This is done via the percentage voltage rise "a"... but I can not logically deduce this me???!!!

Did you or your tips or suggestions???